2x^2=3.25

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Solution for 2x^2=3.25 equation:



2x^2=3.25
We move all terms to the left:
2x^2-(3.25)=0
We add all the numbers together, and all the variables
2x^2-3.25=0
a = 2; b = 0; c = -3.25;
Δ = b2-4ac
Δ = 02-4·2·(-3.25)
Δ = 26
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{26}}{2*2}=\frac{0-\sqrt{26}}{4} =-\frac{\sqrt{}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{26}}{2*2}=\frac{0+\sqrt{26}}{4} =\frac{\sqrt{}}{4} $

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